Algebra

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Let f(x) = 6/x-1 and g(x) = 1+3/x. Please fing the composite function.

This is what i got so far.

=f (1+3/x)

=6/x-1

= =f (1+3/x)
= 6/ [1+3/x - 1]

How do I get the composite?

  • Algebra -

    The definition of a composite function:
    f º g (x) means f (g(x) ), which tells you to work out g(x) first, and then fill that answer into f. See
    (Broken Link Removed)

    In this case,
    f(x) = 6/x-1 and g(x) = 1+3/x
    so
    f º g (x)
    =f(g(x))
    =f(1+3/x)
    =6/(1+3/x)-1
    =6x/(x+3)-1
    =(6x-(x+3))/(x+3)
    =(5x-3)/(x+3)

  • Algebra -

    and the composite function would be?

    A.(fog)(x)= (2x)
    B.(fog)(x) =2/x
    C.(fog)(x)=(6/x-1)(1+3/x
    D.(fog)(x)=1+18/x(x-1)

  • Algebra -

    There is probably a mis-interpretation of the parentheses:
    f(x) = 6/(x-1) and g(x) = 1+3/x
    so
    f º g (x)
    =f(g(x))
    =f(+3/x)
    =6/(1+3/x-1)
    =6/(3/x)
    =2x
    If this is the case, the answer is (A).

  • Algebra -

    This is what I thought as well. Thanks!

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