Physics PLEASE
posted by Physics PLEASE .
I'm trying to derive the formula
v^2 = v0^2 + 2a(xx0)
were zeros are subscripts
my book tells me to derive it this way
use the definition of average velocity to derive a formula for x
use the formula for average velocity when constant acceleration is assumed to derive a formula for time
rearange the defintion of aceleration for a formula for t
then combine equations to get the derived formula for v^2
so here's my work please show me were I won't wrong
def of average velocity = t^1 (x  x0)
(average velocity = t^1(xx0))t=(avearge velocity)t + x0= x  x0 + x0 = x = (average velocity)t + x0
x = (average velocity)t + x0
def of average velocity were costant acceleration is assumed = 2^1(v0 + v)
plug into
x = (average velocity)t + x0
x = 2^1(v0 + v)t + x0
def of acceleration = t^1(vv0)
(a=t^1(vv0))t=(at=(vv0))a^1 = t = a^1(vv0)
t = a^1(vv0)
plug into x = 2^1(v0 + v)t + x0
x = 2^1(v0 + v)a^1(vv0) + x0
solve for v^2
x = 2^1(v0 + v)a^1(vv0) + x0
simplfy
x = (a2)^1(v^2 v0^2)+ x0
(x = (a2)^1(v^2 v0^2)+ x0)2a
(2a)x = (v^2v0^2) + x0
(2a)x  x0 = (v^2v0^2) + x0  x0
(2a)x  x0 + v0^2= (v^2  v0^2) + v0^2
(2a)x  x0 + v0^2 = v^2
so here's what I got for my equation
v^2 = v0^2 +(2a)x  x0
here's what I was suppose to get
v^2 = v0^2 + 2a(xx0)
please show me were I went wrong
thank you!
Show me step by step and as to why because I thing your suppose to subtract x0 from both sides why do you multiply???

You want to show that
V^2  Vo^2 = 2 a (X  Xo)
first rewrite that as:
(VVo)(V+Vo) = 2a (XXo)
now
your average velocity during the interval = (V+Vo)/2
so
X = Xo + t(V+Vo)/2
but
V = Vo + a t
so
t = (VVo)/a
so
X = Xo +(VVo)(V+Vo)/2a
we are there.
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