maths...

posted by .

Differentiate ln [x+√(x^2+1)] with respect to x

hence evaluate limit 0 to 1
∫ 1/√(x^2+1) dx

_________________________________________


Use the identity cos3x=4cos^3x-3cosx,
find ∫cos^3x dx
* Is there a printing error in the question? the limit is from pi/2 to pi/2?!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. mathematics

    ∫▒dx/(x√(2x^2+5x+1)) 2. ∫▒dx/(x√(x^2+4x-2)) 3. ∫▒dx/(sinx+13cosx-11) 4. ∫▒〖(x^2-x+4)ln⁡(x+√(x^2-1) dx)〗 5. ∫▒e^cos2x sin4x dx 6. ∫▒x^3 …
  2. Integration?

    Use the derivatives of sinx and cosx to show that d/dx [tanx] = sec^2 and that d/dx [secx]=sec^2xsinx. Hence evaluate ∫ [1 + sinx]/[cos^2x] dx limit from 0 to pi I know the first part of the question, i'm not sure how i should …
  3. Integration?

    Sorry, i have a load of questions on integration... thanks for any help provided! Evaluate the integrals: limit 0 to pi/4 ∫ [sec^2x]/[5+tanx] dx limit 0 to pi/6 ∫ [3cos3x]/[3+sin3x] dx limit 0 to 3 ∫ [2x-1]/[x^2-x+1] …
  4. maths...

    This is the entire question: A curve has the equation y=(x+2)√(x-1). i)Show that dy/dx = kx/√(x-1) and find k ii)Hence, evaluate limit 2 to 5 ∫ kx/√(x-1)dx My answer: first part, i have already shown, and k …
  5. Integral Calculus

    Solve using Integration by Substitution : ∫√x2-a2/x dx ∫√c2-a dx ∫ ln (√y + 3) dy ∫(5y+4) dy/√5y-1
  6. physics

    1.∫ x³(x+1)dx 2.∫ (1-cot²x)dx 3.∫ cosx(tan x + sec x) dx 4.∫ dx/√5x+8 using u= 5x+8 and using u= √5x+5
  7. physics

    1.∫ x³(x+1)dx 2.∫ (1-cot²x)dx 3.∫ cosx(tan x + sec x) dx 4.∫ dx/√5x+8 using u= 5x+8 and using u= √5x+5
  8. calculus1

    Hi, I have 3 problems here need to be solved, help me please 1.Evaluate ∫ sin2x sec^5(2x)dx 2. If f(x)=√x and P is a partition of [1,16] determined by 1,3,5,7,9,16,find a Riemann sum Rp of f by choosing the numbers 1,4,5,9 …
  9. calculus1

    1. Evaluate ∫(0-4) x/√x^2+9 dx 2. Given F(x)= ∫(0-x) t√t^2+4 dt, find F'(x)
  10. Calculus

    Which of the following integrals cannot be evaluated using a simple substitution?

More Similar Questions