Integration?
posted by Arisa .
Sorry, i have a load of questions on integration... thanks for any help provided!
Evaluate the integrals:
limit 0 to pi/4 ∫ [sec^2x]/[5+tanx] dx
limit 0 to pi/6 ∫ [3cos3x]/[3+sin3x] dx
limit 0 to 3 ∫ [2x1]/[x^2x+1] dx
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By squaring sin^2 + cos^2, show that sin^4x + cos^4x = 1/4 (3+cos4x)
Hence, evaluate ∫(sin^4x+cos^4x) dx
(limit from 0 to pi/8)
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How do i express (2x+1)/(x+3) in the form of p + q/(x+3)???
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