Algebra
posted by Laurie .
Consider the line with equation
5x – 2y = 10.
(a) Find the yintercept for the given line.
(b) Find the slope for a line parallel to the given line.
(c) Find the slope for a line perpendicular to the given line.

(a) Find the yintercept for the given line.
(b)Find the slope for a line parallel to the given line.
(c) Find the slope for a line perpendicular to the given line. 
y intercept is when x = 0
2y = 10
y = 5
2 y = 5 x  10
y = (5/2) x = 5
so m, the slope, = (5/2)
m'= 1/m
m' = 2/5 
This is interesting, I got the first one correct for y = 5 because x = 0 but still do not get how you come up with 5/2 for the slope of the parallel line and the slope of the perpendicular one either? Can you please explain. Thanks!