trig
posted by Peter .
Solve for X. Leave answers in logarithmic forms.
3^(2x) = 2^x
Thanks.

trig 
Reiny
take the logs of both sides
log (3^(2x)) = log (2^x)
(2x)log3 = xlog2
2log3  xlog3 = xlog2
2log3 = xlog2 + xlog3
2log3 = x(log2 + log3)
x = 2log3/(log2 + log3)
or x = 2log3/log6 
trig 
Chris
Ok, I'm kind of confused.
A log's base typically 10 right? Why would you write log 3^(2x)? Shouldn't it be log(sub3) 2x) ?
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