calculus
posted by lana .
find the max point on the graph f(x) = 1/3x^3 + 3x^2  5x

The maximum is where the first derivative is zero, provided the second derivative is negative there.
Solve the equation
f'(x) = x^2 +6x 5 = 0
(x5)(x1) = 0
x = 5 and x = 1 are either maxima or minima. Use the second derivative test to see which is which.
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