algebra
posted by norbert .
you invested $8000, part of it in stock that paid 12% annual interest. however, the rest of the money suffered a 5% loss. if the total annual income from both investments was $620, how much was invested at each rate?

If x was invested at 12%, then 8000x suffered a 5% loss.
0.12x 0.05(8000x) = 620
0.12x  400 + 0.05x = 620
0.17x = 1020
Solve for x
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