Algebra
posted by Nick K. .
Match ABCDE with the solution set below
A. {4/3, 4}
B. {xx > 4 or x < 4/5}
C. No Solution
D. {x 11 < x < 7}
E. All Real Numbers
Solution set
ABCDEx + 9 < 2
ABCDE5x  8 > 12
ABCDE3k + 4 = 8
ABCDEx  6 = 10
ABCDE6x + 8 > 4

It is easier to solve for the unknown and then look for the question.
Working backwards:
x + 9 < 2
Solution set: 7<x<11
check: 7 + 9 =2
11 + 9 = 2
5x  8 > 12
x>4 or x<4/5
3k + 4 = 8
k=4/3 or k=4
x  6 = 10
no solution, ∀ y ∈ ℝ: y ≥ 0
ABCDE6x + 8 > 4
x∈ℝ
Can you take it from here?
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