# Chemistry

posted by .

i need help with a rate law question:

The reaction is

2ClO2(aq) + 2OH -(aq)---> ClO3-(aq)+ ClO2-(aq) + H2O(l)

Experiment 1:

[ClO2]0= 0.0500
[OH-]0= 0.100
INITIAL RATE= 5.75*10^-2

Experiment 2:

[ClO2]0= 0.100
[OH-]0= 0.100
INITIAL RATE= 2.30*10^-1

Experiment 3:

[ClO2]0= 0.100
[OH-]0= 0.050
INITIAL RATE= 1.15*10^-1

a) determine the rate law and the value of the rate constant.

b) what would be the initial rate for an experiment with [ClO2]0= 0.175 mol/L and [OH-]0= 0.0844 mol/L?

• Chemistry -

WHen i did it the answers i got was order of reaction m= 2 and k = 4.6

• Chemistry -

I don't get that.
I have an order of 3 and k = 230
rate = k(ClO2^-)x(OH^-)y.
For x I have 2. For y I have 1. The order overall is 3. Check my work.

## Similar Questions

1. ### Chem

2ClO2 + 2OH- --> ClO2- + H2O Experiment 1, M of [ClO2] = .060 M of [OH-] = .030 Rate of disappearance of ClO2 (M/s) = .0248 Experiment 2, M of [ClO2] = .020 M of [OH-] = .030 Rate of disappearance of ClO2 (M/s) = .00276 Experiment …
2. ### Chem Help .plz

pre-lab questin.. part a was to determine the rate law from the given table... finally i was able to calculate ..rate law which was k[ClO2]2[OH-] since i got m =2 n=1 ..overall order was 3 ... the equation was .. 2ClO2(aq) + 2OH-(aq)---ClO3-(aq) …
3. ### CHEMISTRY!!-

The following date were obtained for the reaction 2ClO2(aq)+2OH(aq)->ClO_3^-(aq)+ClO_2^-(aq) + H2O(l) where rate= delta[ClO_2]/ delta t [ClO_2]0 [OH^-1]0 Initial Rate (mol/L) (mol/L) (mol/L*s) .0500 .100 5.75*10^-2 .100 .100 2.30*10^-1 …
4. ### CHEMISTRY

i need help with this pre lab question:| plse help me! teh following data were obained for the reaction 2ClO2(aq)+ 2OH^-(aq) -> ClO3^-(aq) + ClO2^-(aq) +H2O (l) Where rate = delta[ClO2]/ delta t (mol/L) (mol/L) (mol/L*s) [ClO2]0 …
5. ### chemistry

Chlorine dioxide, ClO2, has been used as a disinfectant in air conditioning systems. It reacts with water according to the following equation. ... HCl If 142.0 g of ClO2 is mixed with 33.0 g of H2O, how many grams of which reactant …
6. ### chemistry

Given the table of Ka values on the right below, arrange the conjugate bases in order from strongest to weakest. Acid Ka HClO 3.5 e-8 HClO2 1.2 e-2 HCN 6.2 e-10 H2PO4- 6.2 e-8 A. ClO2-, ClO¬-, HPO42-, CN- B. ClO2-, HPO42-, ClO¬-, …
7. ### chemistry

If HClO2 is a stronger acid than HF, which is stronger than HOCl, then the order of strengths of the conjugate bases of these acids is ______ < _____ < _____ a) ClO- < F- < ClO2- b) ClO2- < ClO- < F- e) F- < ClO2- …
8. ### chem 1046

An electrochemical cell is based on these two half-reactions: Ox: Sn(s) → Sn2+(aq, 1.74 M) + 2 e- Red: ClO2(g, 0.120 atm) + e- → ClO2-(aq, 1.44 M) Calculate the cell potential at 25°C E Sn>Sn2+ = -.14 E ClO2 = .95
9. ### Chem 1046

An electrochemical cell is based on these two half-reactions: Ox: Sn(s) → Sn2+(aq, 1.74 M) + 2 e- Red: ClO2(g, 0.120 atm) + e- → ClO2-(aq, 1.44 M) Calculate the cell potential at 25°C E Sn>Sn2+ = -.14 E ClO2 = .95