What is the energy of a single photon from a helium -neon laser that emits light 632.8nm?
To find the energy of a single photon of light emitted by a helium-neon laser with a wavelength of 632.8 nm, you can use the equation:
E = hc/λ
Where:
E is the energy of a single photon,
h is the Planck's constant (approximately 6.626 x 10^-34 J·s),
c is the speed of light (approximately 3.0 x 10^8 m/s),
λ is the wavelength of the light.
Now, let's plug in the values:
E = (6.626 x 10^-34 J·s)(3.0 x 10^8 m/s)/(632.8 x 10^-9 m)
When we calculate this equation, we find that the energy of a single photon from a helium-neon laser emitting light at a wavelength of 632.8 nm is approximately 3.14 x 10^-19 Joules.