Algebra (please help!)
posted by Faith .
Mary has a solution that is 60% alcohol and another that is 20% alcohol. How much of each should she use to make 100 milliliters of a solution that is 52% alcohol.
I totally forget how to do this kind of problem. Please help if you can! Thank you so much! :)
let the amount of the 60% solution be x ml
then the amount of the 20% solution must be (100-x) ml
then isn't .6x + .2(100-x) = .52(100) ?
solve for x