9th. algebra

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how can I figure out the formula. example. I need to transform the following equation y = x2 + 4 - 8 into vertex form and then I need to state the coordinates of the vertex of the parabola. I forgot how to arrive at the answer

  • 9th. algebra -

    I will assume there is a typo and you meant
    y = x^2 + 4x - 8

    take 1/2 the coefficient of the x term, square it, then add and then subtract it
    ( 1/2 of 4 is 2 and then squared would be 4)

    y = x^2 + 4x + 4 - 4 - 8

    the first three terms are now a perfect square
    y = (x+2)^2 - 12

    compare this with
    y = a(x-p)^2 + q which has vertex (p,q) and you can conclude that the vertex of
    y = (x+2)^2 - 12 is (-2,-12)

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