prealgebra
posted by y912f .
a field 480,000 m^2 is 160 m wide. What length of fencing is needed to enclose it?
i thought you would just have to do A=lw
480,000= l(160)
l= 3000
but the answer is wrong. the correct answer is in the six thousands.
please help

Ok  as far as you went.
You found the length of one side, which is 3,000 meters.
But the question asks for the length of fencing needed to enclose the field. In other words, you need the perimeter of the field.
P = 2L + 2W
P = ?? 
ohhh, now i get it....6320m
i thought of that at one point, but didn't try doing it
thanks Ms. Sue :) 
You're welcome.