Pre Calc

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I need to graph the function,

y = log(root 3)2x

I did...now I need to graph the inverse. What is that?

  • Pre Calc -

    Are these base 10 logs?
    Do you mean
    y = log (2x)^(1/3)
    ?
    If so then it
    is
    y = (1/3) log (2x)
    inverse
    x = (1/3) log (2y)
    3 x = log 2 y
    10^(3x) = 2 y
    y = (1/2)(1000)(10^x)
    y = 500 (10^x)

  • Pre Calc -

    I am sorry, base 3..
    log base 3 of (2x)

  • Pre Calc -

    y = log(3)2x means that
    3^y = 2x, so

    x = (1/2)*3^y is the inverse function

    You could also write it in inverse function notation as
    f^-1(x) = (1/2)*3^x

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