# pre calc

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log(x)(1/16) = -4/3

this means...

x^(-4/3)= 1/16

so...the -4/3 root of 1/16...

I need to get it in simplest form.

• pre calc -

Continuing,
x^(4/3) = 16
Take the 1/4 root of both sides, and get
x^(1/3)= 2
Cube both sides, and get
x = 8

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