pre calc
posted by MW .
log(x)(1/16) = 4/3
this means...
x^(4/3)= 1/16
so...the 4/3 root of 1/16...
I need to get it in simplest form.

Continuing,
x^(4/3) = 16
Take the 1/4 root of both sides, and get
x^(1/3)= 2
Cube both sides, and get
x = 8
Respond to this Question
Similar Questions

precalculus
What is the base of the function F(x) = b to the power of x if the graph has points of (1/3, 2)and another off the subject one if g(x)= log 7 x what is g(1/49)? 
PreCalc
Hi, I need help writing log(x^29)log(x^2+7x+12) as a single logarithm. Thankyou! since there is a subtraction sign in between that means you divide the two terms...so it would be log(x^29/x^2+7x+12) you can go further and factor … 
PreCalc
I'm stuck on a precalc problem. I need to find y as a function of x, where the constant c is a positive number for In(y1)+In(y+1)= x+c express your question as ln[(y1)(y+1)] = x+c change that to exponential form e^(x+c) = (y1)(y+1) … 
algebra
write (27a^3)^(2/3) in simplest form. solve log(6x+11)=2 please and thanks I need to see your work on the first. On the second, take the antilog of each side what is the antilog? 
Math radical form
Find the distance of the line segment whose endpoints are (5,7) and (2,3) in simplest radical form. sqrt [(73)^2 + (5 (2))^2] = sqrt [16 + 49] = sqrt 65 That is the simplest form I can think of. sqrt means "square root of" 
Pre Cal (logs)
I need help with these logs 1: Log underscore4 16X 2: 2 Ln ( X(sqr. root)e 3:5^[2logUnderscore5(3x)] 4:log underscore2 ^[1280logunderscore2 5) I don't understand how to do them thanks 
Pre Calc
I need to graph the function, y = log(root 3)2x I did...now I need to graph the inverse. What is that? 
Pre Calculus
Evaluate log b {square root of 10b}, given that log b 2 = 0.3562 and log b 5 = 0.8271 (sorry I had no clue how to type this in math format!) 
Precalculus
PLEASE HELP ME WITH THESE QUESTION AS MUCH AS POSSIBLE!! Evaluate without a calculator. Give exact answers: a) log(log(10)) = ? 
PreCalc/Trig...
Write the equation y = log x in exponential form.