chemistry help
posted by chris .
A solution of AgNO3 contains 29.66 g of solute in 100.0 mL of solution. What is the molarity of the solution?

moles = grams/molar mass.
M = moles/L of solution. 
29.66/100.0=.2966 molar mass
i don't know where to go from here. 
The molar mass of AgNO3 is not 100. Add up atomic mass Ag, N, and three O atoms to get the molar mass (the periodic tab le will give you the atomic masss).
Then 29.66 g/molar mass = moles AgNO3.
Then moles AgNO3/liters of soln= M.
(They tell you the solution is 100 mL. That's 0.100 L. 
Molecular weight os AgNO3 = 169.87
You have 29.66 g, therefore you have 29.66 / 169.87 moles = 0.174 moles. This is in 100 ml. Molarity is moles per liter, so, 0.174 x (1000/100) = 1.75. Concentration of the solution = 1.75 M. Worked out with chemCal for the iPhone/iPod Touch.
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