PreAlgebra
posted by mysterychicken .
Can someone show me how to answer these questions stepbystep? Thanks!
Solve the equation for y in terms of x
1.2x + 7= y
2. x 2/3y= 3
3.12x + 3y = 48
Give any three ordered pairs that are solutions of the equation
4. 1/4y  x =0
5. 5x  y= 5
MC

to solve for y in terms of y just set the equation equal to y. Then divide everything by the coefficiant of y.
#1) 2x+7=y (already correct)
#2) x(2/3)y=3
x3=(2/3)y (move y by itself)
(x3)/(2/3)=y (divide by 2/3)
>(3x9)/2=y (simplify) 
12x + 3y = 48
add 12x to both sides
3y = 12x + 48
divide all terms by 3
y = 4x + 16

1/4y  x = 0
start as above: solve for y
add x to both sides
1/4y = x
multiply all terms by 4
y = 4x
Now plug in 3 values for x (such as 1, 0, and 1) and find the value for y for each. The three resulting (x,y) pairs are ordered pairs.
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