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7th grade algebra

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the difference between a father's age and his son's age if the father's age is three times his son's age

  • 7th grade algebra -

    Let f = father's age and s = son's age.

    "the father's age is three times his son's age"

    f = 3s

    "the difference between a father's age and his son's age"

    f - s

    If we want to know f - s, and have f = 3s, then we need to subtract s from the left side. And what we do to one side of an equation we must to the other side as well, so we subtract s from both sides.

    (f) - s = (3s) - s
    f - s = 2s

    Now try some numbers for the son's age.

    If the son is 14 (s = 14), then the difference between the father's and son's age would be 2s = 2(14) = 28. Does that work? The father is 3x the age of the son, so if the son is 14, the father is 3 x 14 = 42. And yep, 42 - 14 = 28.

    If the son is 17 (s = 17), then the difference between the father's and son's age would be 2s = 2(17) = 34. Does that work? The father is 3x the age of the son, so if the son is 17, the father is 3 x 17 = 51. And yep, 51 - 17 = 34.

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