Question:
Sandy, has fewer than 16 crayons. If she puts them in equal rows of 5, none are left over. If she puts them in equal rows of 6, four are left over. How many crayons are there?
two rows of fives=10
one row of sixes=6
10-6=4 crayons left over.
I think the answer is 10 crayons.
Thanks.
two rows of 5=10 and 2 rows of 6= 12 16-12=4 so she had 4 left after rows of six so yes i agree she has 10 crayons :]
I think I'm right but not sure if the second part of your answer is right? But I think mine is.
oh yea i got confused because 2 rows = 10 and none left so rows of 6 with 4 left would be 1 row of 6 and 4 left so yea she has 10 crayons sorry i got confused! it is easy to get confused on the simplest of problems thanks 4 noticing !
Thanks, no problem.
yep :]
To solve this problem, we can use a system of equations.
Let's represent the number of crayons Sandy has as "x".
According to the information given, we know that:
1) When the crayons are put in equal rows of 5, none are left over.
This can be represented as: x = 5n, where n is the number of rows of 5.
2) When the crayons are put in equal rows of 6, four are left over.
This can be represented as: x = 6m + 4, where m is the number of rows of 6.
Now, we can use these equations to solve for the value of x.
From equation 1, we can rewrite it as:
x = 5n
Substitute this value of x into equation 2:
5n = 6m + 4
Now we need to find values of n and m that satisfy this equation.
We can start by substituting some possible values for n and see if we get an integer value for m.
Let's try n = 1:
5(1) = 6m + 4
5 = 6m + 4
1 = 6m
This doesn't give us an integer value for m. Let's try n = 2:
5(2) = 6m + 4
10 = 6m + 4
6 = 6m
m = 1
This gives us an integer value for m. Therefore, we've found a solution where n = 2 and m = 1.
Now, plug these values back into either equation to find the value of x:
x = 5n
x = 5(2)
x = 10
Therefore, there are 10 crayons in total.