chem

posted by .

The bond enthalpy of N2(g) is 418.0 kJ/mol. Calculate ÄH°f for N(g).

I figured that if it gave the enthalpy for N2, then the enthalpy for N would be half of the given amount. But that wouldn't be bonded to anything??

Is there a standard calculation?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chem

    Bond enthalpy is the energy required to break a mole of a certain type of bond. O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523 kj/mol Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction: 2SF4 + …
  2. CHem help pkz

    Bond enthalpy is the energy required to break a mole of a certain type of bond. O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523 kj/mol Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction: 2SF4 + …
  3. ap chem

    calculate the lattice enthalpy of potassium fluoride from the following data: enthalpy of formation of K(g): +89 kJ · mol−1 first ionization energy of K(g): +418 kJ · mol−1 enthalpy of formation of F(g): +79 kJ · mol−1 …
  4. Chemistry

    The bond enthalpy of N2(g) is 418.0 kJ/mol. Calculate ÄH°f for N(g).?
  5. Chem

    The bond enthalpy of N2(g) is 418.0 kJ/mol. Calculate delta H°f for N(g).?
  6. chemistry-Thermochemistry (grade 12)

    calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) …
  7. chemistry-Thermochemistry (grade 12)

    calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) …
  8. Chemistry

    Reposted: Use Hess's law to calculate the enthalpy change for the reaction: 3C(s) + 3H2(g) yield C3H6(g) Given the following thermochemical equations: 2C3H6(g) + 9O2(g) yield 6CO2(g) + 6H2O(l) enthalpy change= -4116.0 kJ/mol C(s) + …
  9. CHEM:

    The bond enthalpy of the Br−Cl bond is equal to ƒ¢H‹ for the reaction BrCl(g) ¨ Br(g) + Cl(g). Use the following data to find the bond enthalpy of the Br−Cl bond. Br2(l)--->Br2(g) ƒ¢H=30.91 KJ/mol Br2(g)--->2Br2(g) …
  10. chemistry

    use the following data to calculate the mean bond enthalpy values for the C-H and C-C bonds. CH4(g)-C(g) + 4H(g) standard enthalpy change is +1648 kj/mol C2H6(g)-2C(g) + 6H(g) standard enthalpy change is +2820 kj/mol

More Similar Questions