Chemistry
posted by Jessi .
A 2% solution of Hydrochloric acid is required for a procedure. A 5% solution is availabe. How much of the 5% solution will be required to make 1 L of solution?

Are these 5% and 2% massvolume?
To dilute a 5% solution to a 2% solution, we need to dilute it by a factor of 2.5 (2/5 = 1/2.5).
So a 5% solution contains 5 g HCl/100 mL solution. So if we end up with 1000 mL of solution, how many g HCl must be there to be 2%. X/1000 = 0.02 = 2,000 g. With a solution that is 5 g/100, how much must we use to obtain 2,000 g? That will be 2000/5 = 400. So we take 400 g of the 5% solution, make to 1000 mL, and we have a 2% solution.
See if you can come up with some helpful hints for the other posts that concern concn.
Respond to this Question
Similar Questions

chemistry
What is the molarity of a potassium hydroxide solution if 38.65 mL of the KOH solution is required to titrate 25.84 mL of 0.1982 M hydrochloric acid solution? 
Chemistry
Is this answer correct? Calculate the molar concentration of sodium hydroxide solution if 36.00mL of this solution were required to neutralize 25.00 mL of a 0.2000 M solution of hydrochloric acid. .0288M? 
Chemistry
a titration experiment 20 mL solution of hydrochloric acid required 15.2mL of a .879 M barium hydroxide solution. What was the molar concentration of the HCl solution? 
chemistry
a sodium hydroxide solution was prepared according to the procedure outlined in this weeks experiment. This sodium hydroxide solution was standardized by by titration against exactly 10mL of a 0.28M hydrochloric acid solution. In three … 
Chemistry
You are using concentrated hydrochloric acid solution (12.0 M)to make 445.0 ml of a 5.85 M solution. Calculate the number of milliliters of concentrated HCl required to make the solution. 
chemistry
Solution A:50cm^3 of 1.0mol dm^3 hydrochloric acid,HCl Solution B:10cm^3 of 2.0mol dm^3 hydrochloric acid,HCl (a)Calculate the number of moles of hydrochloric acid,HCL in each solution. (b)Solution A and B are mixed together. (i)Calculate … 
Chemistry
A given solution contained potassium chloride, KCl, and hydrochloric acid. 25 cm3 of it needed 24.80 cm3 of 0.0986 M sodium hydroxide solution to neutralize the acid, and the neutral solution then required 23.55 cm3 of 0.2 M silver … 
Chemisrty
You wish to make a 0.195 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? 
Chemistry
If 0.176 g of pure sodium hydroxide was dissolved in water and the solution titrated with 5.05 mL of hydrochloric acid solution to a phenolphthalein end point, calculate each of the following of the hydrochloric acid solution. (a) … 
Chemistry
(1)Make 500 ML of 4N H3PO4. How many grams will be needed?