posted by Angie .
How are you supposed to write an equation for the line that is parallel to the given line and that passes through the given point? For ex., what do you do for y = 3/4 x - 9, (-8,-18)?
since the line is parallel to the old one, the slope of the new one must be the same as the slope of the old one.
the new equation must be
y = (3/4)x + b
plug in the given point to find b,
put b back in the above equation and you are done.
thanks..in your opinion, is the way you did easier than doing it with point-slope form?