Calc
posted by Phil .
Find the point on the line 2 x + 7 y + 4 =0 which is closest to the point ( 0, 1 )

let P be that point
slope of given line is 2/7
so slope of line from P to (0,1) is 7/2
and since (0,1) is the yintercept,
its equation is y = (7,2)x + 1
solve the two equations to find P
use substitution, i.e.,
2x + 7((7/2)x + 1) = 4
etc 
i found x value of P how do I find the y value of P?

sub it back in the original equation.
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