Pre Cal.

posted by .

Evaluate tan(cos^(-1)(ã3/2 )+tan^(-1)(ã3/3))?

arccos(sqrt(3) / 2) = pi / 6
arctan(sqrt(3) / 3) = pi / 6
tan(pi / 6 + pi / 6)
= tan(pi / 3)
= sqrt(3).

  • Pre Cal. -

    Evaluate tan(cos^(-1)(sqrt 3)/2))+tan^(-1)((sqrt 3)/3))?

  • Pre Cal. -

    tan(cos^(-1)(sqrt 3)/2))+tan^(-1)((sqrt 3)/3))
    = tan( pi/6) + pi/6
    = 1/√3 + pi/6

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Trig

    Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v - u) tan (v + u) First compute or list the cosine and sine of both u and v. Then use the combination rules sin (v + u) = sin u cos …
  2. calculus

    Calculate definite integral of dx/(x^4 * sqrt(x^2 + 3)) Over (1,3) I start with the substitution x = sqrt(3)*tan t so: sqrt(x^2 + 3) = sqrt(3) * sec t dx = sqrt(3) * sec^2 t dt x^4 = 9 * tan^4 t The integral simplifies to: = dt/(tan^3 …
  3. calculus

    Integrate: dx/sqrt(x^2-9) Answer: ln(x + sqrt(x^2 - 9)) + C I'm getting the wrong answer. Where am I going wrong: Substitute: x = 3 * sec t sqrt(x^2 - 9) = sqrt(3) * tan t dx = sqrt(3) * sec t * tan t Integral simplifies to: sec t …
  4. Calculus

    Calc length of arc of y=ln(x) from x=1 to x=2 ---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x = 1/tan^2 t sqrt(1+1/x) = sqrt(1+tan^2 t) = sec t dx = -2 * tan^-3 t * sec^2 t dt Integrate over x=(1,2): …
  5. Trig

    Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4). (0 is not the number zero I don't know what its called) I have to find r first. r=sqrt x^2+y^2 r=sqrt …
  6. Math

    1.Write the equation 5x+y-2=0 in normal form. 5x+y-2=0 5x+y=2 (add two to both sides) Standard form (Ax+By=C)---> 5x+y=2 Y-intercept (when x equals 0) 5x+y-2=0 5x+y=2 5(0) +y=2 y=2 X-intercept (when y equals 0) 5x+y-2=0 5x+y=2 5x+0=2 …
  7. Math(Please check!!!)

    1) Evaluate (if possible) the sine, cosine, and tangent of the angles without a calculator. a) 10pi/3 Sin = -sqrt 3/2 Cos = -1/2 Tan = sqrt 3 Are these correct ?
  8. Pre-cal (Please Check)

    1) Evaluate (if possible) the sine, cosine, and tangent of the angles without a calculator. a) 10pi/3 Sin = -sqrt 3/2 Cos = -1/2 Tan = sqrt 3 Are these correct ?
  9. Math

    tan(-120)= sqrt 3 OR - sqrt 3 (Helper stated that it was sqrt 3) But, I'm just confused over this part: for even vs. odd functions it saids that tan(-angle) = - tan(angle) so the even vs. odd doesn't matter since tan is positive in …
  10. Maths Calculus Derivatives

    Find the first derivative for the following functions 1) f(x) = sin(cos^2x) cos(sin^3x) 2) f(x) = ( tan 2x - tan x ) / ( 1 + tan x tan 2x ) 3) f(x) = sin { tan ( sqrt x^3 + 6 ) } 4) f(x) = {sec^2(100x) - tan^2(100x)} / x

More Similar Questions