Stats
posted by Sue .
Test the claim that the mean body temperature is less than 98.6 using a= 0.05. Assume a smaple of 16 yilded a mean of 98.2 with a standard deviation of 0.6

Z = difference between means/√SE^2
SE = SD/√(n1) (or just √n)
Look up value in table in back of statistics text labeled something like "areas under normal distribution.
I hope this helps. Thanks for asking.