There is a total of 37feet of lumber? You may use as much of this as you need.
Your class has raised $121.00 to buy the sand. A bag of sand costs $1.50. One bag will cover an area of one square foot.
What is the largest sand-filled area you can make for the money and lumber you have?
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To find the largest sand-filled area you can make with the given amount of money and lumber, we need to consider two factors: the amount of lumber available and the budget for purchasing sand.
First, let's calculate how many bags of sand you can purchase with the given budget:
Total budget = $121.00
Cost of one bag of sand = $1.50
Number of bags of sand you can buy = Total budget / Cost of one bag of sand = $121.00 / $1.50 = 80 bags (rounded down to the nearest whole number).
Next, let's consider the amount of lumber available. Although there is no specific measurement given for the lumber, we know that there is a total of 37 feet available.
Now, let's assume that you want to create a rectangular area using the lumber, where the length is greater than or equal to the width. To maximize the area, let's assume that the length is equal to the available lumber, and the width is as close as possible to a square shape.
Let's start by calculating the square root of the total lumber available to determine the dimensions of the square area:
Square root of 37 feet = √37 ≈ 6.08 feet
Since we cannot have a fraction of a foot, we will round down the width to 6 feet. Therefore, the length will be 37 feet.
Now, let's calculate the area of the rectangle:
Area = Length × Width = 37 feet × 6 feet = 222 square feet
Finally, since each bag of sand covers one square foot, the maximum sand-filled area you can create with 80 bags is 80 square feet.
So, the largest sand-filled area you can make with the given budget and lumber is 80 square feet, using a rectangular area measuring 37 feet long and 6 feet wide, and filling it with 80 bags of sand.