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The length of a rectangle is 5 ft more than the width. If the area of the rectangle is 36 sq. ft what are the dimensions of the rectangle?
(Please provide steps/explanation to solve this problem.)

Let d length be y and the width be y-5 .y times y-5 =36.y times y-5 minus 36=0.then factorise

The answers are-4 and 9.to check 9(9-5)=36 or -4(-4-5)=36

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