Independent and dependent events
posted by jaz
A six-sided-cube is labeled with the numbers 1, 2, 2, 3, 3, and 3. Four sides are colored red, one side is white, and one side is yellow. Find each probability.
Tossing 2, then 2.
Tossing red, then white, then yellow.
can you show me how to start
Prob(2, then another 2) = 2/6 * 2/6 = 1/9
Prob(red,white,yellow) = 4/6 * 1/6 * 1/6 = 1/54
these are the answers for them
For the first one there are 6 possible numbers, two of which are 2. So the probability of rolling a 2 is 2/6.
If these are independent then the probability of throwing another 2 is also 2/6.
The probability of the combined two events is the product of the probabilities thus
2/6*2/6 = 1/9
The same approach is taken for the coloured sides.