# Calculus

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Determine the area of the region enclosed by the limaçon
r=5+2sin(theta)

• Calculus -

You have to integrate 1/2 r^2 from theta = 0 to 2 pi.

1/2 r^2 = 1/2 [25 + 20 sin(theta)
+ 4 sin^2(theta)]

The sin(theta) term doesn't contribute to the integral and sin^2(theta) can be replaced by 1/2 [because it would yield the same contribution as cos^2(theta) and together they are equal to 1].

So, the area is given by:

pi[25 + 2 ] = 27 pi

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