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Calculus

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Given the equation xy = 2, set up an integral to find the length of path from x = a to x = b and enter the integrand below.

I did the integral from b to a and set it equal to the sqrt(1+4/x^4), because I found y to equal 2/x and the derivative to be -2/x^2, but I think I am solving the problem wrong.

  • Calculus -

    y = 2/x (The is the integrand). The derivative is -2/x^2
    When calculating the length of a line, you have to integrate sqrt[1 + (dy/dx)^2], which in this case is
    sqrt[1 + 4/x^4]. That function is the integrand.

    Your last step is wrong.
    The line length from a to b is the difference in the values of the INTEGRAL of sqrt[1 + 4/x^4] dx at the two end points.

    I don't have a clue abut how to integrate that function, but they are only asking you to set up the integral anyway.

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