the lcm is 30 the gcf is 2 whats the pair of numbers for each set of conditions

thats sooooooo wrong

30 is the least common multiple of:

1, 30
2, 15
3, 10
5, 6

However, 2 is not the greatest common factor of any of those pairs.

To find the pair of numbers that satisfy the given conditions, we need to find two numbers whose least common multiple (LCM) is 30 and greatest common factor (GCF or GCD) is 2.

To approach this problem, let's first find the prime factorization of 30 and 2.

The prime factorization of 30 is:
30 = 2 * 3 * 5

The prime factorization of 2 is:
2 = 2

Now, let's determine the pair of numbers that fulfill the conditions:

1. LCM is 30
We know that the LCM of two numbers is found by taking the product of the highest powers of all prime factors occurring in either number. So, we need to find two numbers that contain the prime factors of 30.

Let's choose one number with the prime factors 2, 3, and 5. So, a possible number could be:
2 * 3 * 5 = 30

Since we are asked for a pair of numbers, let's choose a second number that contains some or all of the prime factors of 30.

Let's select another number with the prime factors 2 and 3. So, a possible number could be:
2 * 3 = 6

Hence, one possible pair of numbers with an LCM of 30 is (30, 6).

2. GCF is 2
The greatest common factor (GCF) or greatest common divisor (GCD) of two numbers is the largest number that divides both numbers evenly. Since the GCF is 2, both numbers have to be divisible by 2.

Let's select one number that is divisible by 2. So, a possible number could be:
2 * 1 = 2

Now, let's choose a second number that is also divisible by 2. Another possible number could be:
2 * 2 = 4

Hence, one possible pair of numbers with a GCF of 2 is (2, 4).

In summary, the pair of numbers that satisfy the given conditions is:
- For the condition LCM is 30: (30, 6)
- For the condition GCF is 2: (2, 4)

lcm(x,y) = x y/gcf(x,y) --------->

x y = 60 = 2*2*15

So, we can take x = 2 and y = 30.