I have my solution to this problem but I am not very confident in it being correct. I just want to see if some one else comes up with the same answer.
Solve (x^2 - 2x)(x + 3) = -2x(x = 1)
I think you meant
(x^2 - 2x)(x + 3) = -2x(x + 1) since the = and + signs are on the same key
after expanding and simplifying I got
x^3 + 3x^2 - 4x = 0
x(x^2 + 3x - 4) = 0
x(x+4)(x-1) = 0
so x = -4,0,1
how does that compare with yours ?
Reiny how did you get to the -4x? I came up with -8x which does not allow for any more reduction.
x^3 + 3 x^2 -2 x^2 - 6 x + 2 x^2 + 2 x = 0
note that -6x + 2 x = -4x
x^3 + 3 x^2 -4 x = 0
x ( x^2 + 3 x - 4) = 0
To verify if your solution is correct, you can compare it with someone else's solution. However, in this case, you have not provided your solution.
To find a solution to the equation, follow these steps:
Step 1: Expand the left side of the equation:
(x^2 - 2x)(x + 3) = x(x + 3) - 2x(x + 3)
= x^2 + 3x - 2x^2 - 6x
Step 2: Simplify the equation:
x^2 + 3x - 2x^2 - 6x = -2x(x = 1)
= x^2 + 3x - 2x^2 - 6x = -2x
Step 3: Combine like terms:
-x^2 - 3x - 6x = -2x
Step 4: Rearrange the equation to one side:
-x^2 - 3x - 6x + 2x = 0
-x^2 - 7x = 0
Step 5: Factor the equation:
-x(x + 7) = 0
Step 6: Set each factor equal to zero:
x = 0 or x + 7 = 0
Step 7: Solve for x:
x = 0 or x = -7
Now that you know the solutions are x = 0 and x = -7, you can compare them with your solution to see if they match.