a soln. that is .195 M in CH3NH2 and .105 M in CH3NH3Br
what is the balanced equation for this ? How do you know ?
I'm thinking its
CH3NH3Br + H2O <====>H3O + CH3NH2
is this correct ?
Your equation looks ok to me but this looks like a buffer solution to me. Do you have a buffer problem? If so, use the Henderson-Hasselbalch equation to solve for the pH or the pKaa.
The balanced equation for the reaction between CH3NH2 (methylamine) and CH3NH3Br (methylammonium bromide) can be determined through observation, or by looking up the reaction in a chemical database.
Typically, when methylamine reacts with methylammonium bromide, the bromide ion (Br-) from CH3NH3Br is replaced by the hydroxide ion (OH-) from methylamine, resulting in the formation of water (H2O) and the salt methylammonium hydroxide (CH3NH3OH).
The balanced equation for this reaction is:
CH3NH2 + CH3NH3Br → CH3NH3OH + H2O
Please note that this is a general representation of the reaction, and the actual reaction conditions may vary.
To determine the balanced equation for this solution, we first need to identify the chemical species present in CH3NH2 and CH3NH3Br.
CH3NH2 is methylamine, and its chemical formula is CH3NH2. It is a weak base.
CH3NH3Br is methylammonium bromide, and its chemical formula is CH3NH3Br. It is the salt form of methylamine, where the hydrogen on the nitrogen of methylamine is replaced by a bromide ion.
Now let's figure out what happens when the two solutions mix.
When CH3NH2 dissolves in water, it undergoes hydrolysis and ionizes to produce hydroxide ions (OH-) and the conjugate acid, CH3NH3+.
CH3NH2 (aq) + H2O (l) ⇌ CH3NH3+ (aq) + OH- (aq)
On the other hand, CH3NH3Br dissociates in water to release CH3NH3+ ions and bromide ions (Br-).
CH3NH3Br (aq) ⇌ CH3NH3+ (aq) + Br- (aq)
So, the balanced equation for this solution is:
CH3NH2 (aq) + H2O (l) + CH3NH3Br (aq) ⇌ 2 CH3NH3+ (aq) + OH- (aq) + Br- (aq)
To determine this equation, we use our knowledge of the ionization properties of CH3NH2 and the dissociation properties of CH3NH3Br when they are dissolved in water.