The name of one of the compounds given on my worksheet is Molybdenum V. But according to my periodic table, there is no MOlybdenum with a charge of 5. How could this be right? Thanks for looking into this!!
yes it could be 6, 5, 4, 3, or 2
if your periodic table isnt detailed enough it probably wont say
Mo V is not widely known but MoF5 and MoCl5 are known. The MoF5 occurs as the tetramer (MoF5)4 and MoCl5 as the dimer (MoCl5)2.
To understand why there is a compound named "Molybdenum V" even though there is no molybdenum ion with a charge of 5, we need to consider the concept of oxidation states.
Oxidation states, or charges, indicate the number of electrons that an atom has gained or lost when it forms a chemical compound. In most cases, elements tend to gain or lose electrons to achieve a stable electron configuration, typically by achieving a full valence shell.
Molybdenum (Mo) is a transition metal, and transition metals often have multiple oxidation states. The most common oxidation states of molybdenum are +2, +3, +4, +5, and +6. However, it is uncommon for molybdenum to exist in its +5 oxidation state in simple ionic compounds.
In cases where the oxidation state of an element is not a whole number, it is common to use Roman numerals to represent the oxidation state. For example, "Molybdenum V" refers to molybdenum in its +5 oxidation state.
It is important to note that the actual chemical formula for a compound containing molybdenum in its +5 oxidation state, such as molybdenum oxide (MoO5), may not exist or may be highly unstable. However, for the purpose of your worksheet or textbook, the compound "Molybdenum V" is likely used to denote the concept of molybdenum in its +5 oxidation state.
In summary, while there is no stable molybdenum ion with a charge of +5, the designation "Molybdenum V" is likely used as a simplified representation of molybdenum in its +5 oxidation state.