Algebra
posted by A.W. .
How do I solve for elimination method on this problem: 0.3x  0.2y=4 and 0.3x + 0.3y= 5/19. I know that multiply by 10 on both equations and get 3x2y=40 and 3x+3y=50/19. and then I have to multiply 3x3y=40 by 3 and 3x+3y= 50/19 by 3 to get 9x9y=120 and 9x9y=150/19. But from there I get lost. Can someone please help me?

I just did your earlier problem. Please study that. If you can do one you can do them all.

first if you have .3 x in both, why multiply by 10?
.3 x  .2 y = 4
.3 x + .3 y = 5/19
subtract second from first
0 x  .5 y = 71/19
y =  142/19
so
.3 x  .2 (142/19) = 40
3 x = 2(142/19) + 760/19
3 x = 476/19
x = 476/57
Respond to this Question
Similar Questions

Algebra
Solve each literal equations for the indicated variable D = C  s/n ( for s) s/n = D  C Next, multiply both sides of the above equation by n, to get the equation for s. i don't understand could you type it how it looks This is an … 
algebra
if you have the sign of > or < does this also mean = ? 
Algebra
Solve S=a/(1r) for r S = a/(1r) Multiply both sides by 1r S*(1r) = [(1r)*a]/(1r) Simplify S*(1r) = a Multiply terms on the left. S  S*r = a Subtract S from both sides. SS*r  S = a  S Simplify S*r = a  S Multiply both sides … 
need guidance on an algebra problem
20 x+3(y1)=11 2(xy)+8y = 28 multiply out 20 x+3y3=11  Is this correct? 
Algebra
Solving system of linear equations by using the apropiate method name the method and the x,y coordinates 1)X=4y+8 2x8y=3 2)3x7y=6 elimination method 2x+7y=4 (2,0) 3)5x2y=12 elimination method 3x2y=2 (7,23/2) 4)9x8y=42 elimination … 
math
How do I solve the equations using the elimination method: .3x.2y=4 and .4x +.3y= 49/23 Normally I would multiply the decimals by 10 to make them whole numbers, but that fraction is really throwing me off. What do I multiply to eliminate … 
Algebra
89. Solve for x in the equation: 6/7x  6 = 2 I posted this before, and this is the reply I got from someone: multiply both sides by 7 6x42=14 add 42 to each side 6x=28 x=14/3 But I don't get how this is done because to eliminate … 
Math
The problem to solve is: (x+20)(x12)(x+4)>0 but I can't figure out how to do this right so I left off the >0 and tried to solve the equation. x+20 evaluates to x+20 x12 evaluates to x12 Multiplying x+20 by x12 is a classic … 
Math
I am really have a tough time trying to solve this problem. I think my first three steps are correct but I am not sure. Could someone please help me? 
math
What would you need to multiply by in order to solve this system of equations using the linear combination (elimination) method?