Calculus
posted by Anonymous .
Use integration by parts to find the given integral:
∫_9^1 (7t  42)e^(7  t)
= [28(1 + e^8)] / e^2
Is my answer correct?
or... is it..
= 70e^(2) + 14e^6

Is your 9^1 a misprint? What is the purpose of the 1? Why is there no "dt" in your integral?
Both of your answers are incorrect, since they are constants. The indefinite integral would be a function of t, and the definite integral would have to have specified limits of integration. You did not mention any. 
it's 1^9 and I forgot to include dt... and I need to evaluate it when f(9)  f(1) and that's what my answer represents..
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