prealgerbra

posted by .

what is the answer to simplifying this equation:

25a^-2 b^-5 c^8/40 a^5 c^9

• prealgerbra -

(25a^-2 b^-5 c^8)/(40 a^5 c^9)

I made changes assuming that is what you meant.
= 5/(8a^7 b^5 c)

Usually, it is considered simplified if no negative exponents are hanging around.
check with your teacher what they consider "simplified"

Similar Questions

1. Calc.

For the function ƒ(x) = x^3 - 8x + 3, calculate where a = 5 and h = 2. Simplify before substitution (the simplifying is where I am having problems...not sure if my answer is right). Thanks. Using the limits equation.
2. Calculus; Limits

Evaluate limit, x -> a, [(x + 4a)^2 - 25a^2] / [x - a] My work: = limit, x -> a, (x^2 + 8ax + 16a^2 - 25a^2) / (x - a) = limit, x -> a, (x^2 + 8ax - 9a^2) / (x - a) = limit, x -> a, (x + 8a - 9a^2) / (-a) = (a + 8a - 9a^2) …
3. Simplifying (Math)

[a + (8a^-2)] / [1 + (2a^-1)] and [(x^-1) + (y^-1)] /[(x^-1) - (y^-1)] No idea where to begin simplifying. Suggestions and help are greatly appreciated.

5. math

perform indicated operations. (a+3)/(5a+25)-(a-1)/(3a+15) (a+3)/5(a+5)-(a-1)/3(a+5)=(a+3)5(a+5)/5(a+5)3(a+5)-(a-1)5(a+5)/5(a+5)3(at5)= 5a^2+25a+15a+75+5a^2+25a-5a-25/5(a+5)3(a+5) i got (10a^2+60a-50)/5(a+5)3(a+5)and that's wrong. where …
6. prealgerbra

What is the answer to x/8-12=10 we need to find x i don't get how to do it need it quickly please help me

-22+y=y/-14
8. Math

How would I simplify this quadratic equation: y=-15/20.25(x^2+3x+2.25)+0 This is my work already done the original equation I was given but I need help simplifying the equation I have found.
9. math

a) 25a^2 - 16a^2 b^2 b) x^2 - (a+b)^2 c) 9(x-y)^2 - z^2 d) 16x^4 - 81y^4 e) 25a^2 - 16a^2 b^2
10. Math

1. All real numbers that are less than -3 or greater than or equal to 5 A. x<-3 or xâ‰¥5*** B. x<5 or xâ‰¥-3 C. xâ‰¤-3 or x>5 D. xâ‰¤-3 or xâ‰¤5 2. The time a cake must bake is between 25 minutes and 60 …

More Similar Questions