algebra
posted by Kevin .
solve system of equation
5x+2y+z=25
5x3yz=23
3x+y+2z=9

I would use elimination and start with the z's
Add the first plus the second to get
10x  y = 48
Double the second and add it to the third to get 13x  5y = 55
ahhh, changed my mind, let's now switch to substitution
from above 10x  y = 48 or
y = 10x + 48
sub that into
13x  5y = 55
13x  5(10x + 48) = 55
etc. (I got x=5)
I am sure you can finish it from here. 
I am coming up with (5,2,4) for my answer and I see you x=5

good job
You can tell your answers are correct by merely subbing them back into the 3 original equations, they work
TRUST YOURSELF
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