trig help again i cant get any of these

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sin^4cos^2x=(1/16)(1-cos 2x)(1-cos4x)


work one 1 side only!

  • trig help again i cant get any of these -

    pick x=50ยบ
    LS = .202..
    RS = .379..

    Your equation is NOT an identity

    I assumed your LS = sin^x4cos^2x
    you had sin^2[cos^2x], but I doubt that is what you meant.
    (that would be even worse)

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