Algebra
posted by Willow .
The perimiter of a lot is 190 meters. The width is onefourth of the length. Find the dimensions.
Here's my system of equations:
2w + 2L = 190
1/4L = w
What would I do from here? I prefer the elimination method. Would I multiply the second equation by 4? When I did so, it kind of messed up the equation.
Thanks! :)

I would use substitution, but if you insist on using elimination, multiplying the second equation by 4 gives you
L = 4W or 4W  L = 0
now double that:
8W  2L = 0 , now the first:
2W + 2L = 190, now add them
.
.
.
I'm sure you can finish it. 
Did you get w = 19 and L = 76?
Thanks! :) 
yes, correct!
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