chemistry
posted by i need help! .
45.00 mL of 1.45×10−2 M HI(aq) is mixed with 75.00 mL of 1.06×10−2 M KOH(aq).

chemistry 
i need help!
Sorry, I forgot to mention what the actual question was using the information I just posted.
What is the pH of the final solution?
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