Write Sulfuric acid and potassium hydroxide where the products are potassium sulfate and water.
H2SO4 + 2KOH ==> K2SO4 + 2H2O
thank you!
To write the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) to form potassium sulfate (K2SO4) and water (H2O), we need to know the formulas and charges of the ions involved.
The formula of sulfuric acid is H2SO4. It dissociates in water to form two hydrogen ions (H+) and one sulfate ion (SO4^2-).
The formula of potassium hydroxide is KOH. It dissociates in water to form one potassium ion (K+) and one hydroxide ion (OH-).
Now, let's balance the equation step by step:
Step 1: Write the reactants and products based on their formulas:
H2SO4 + KOH → K2SO4 + H2O
Step 2: Balance the number of atoms by adjusting the coefficients:
H2SO4 + 2KOH → K2SO4 + 2H2O
Now, the equation is balanced, showing that one molecule of sulfuric acid reacts with two molecules of potassium hydroxide to produce one molecule of potassium sulfate and two molecules of water.