Calculus
posted by Shannon .
Evaluate the indefinite integral: 8xx^2.
I got this but I the homework system says its wrong:sqrt((x8)x)/(2*sqrt(x8)*sqrt(x))*(((sqrt(x8)*(x4)*sqrt(x))32*log(sqrt(x8)+sqrt(x))

How on earth did you get that mess? Just add the separate integrals of 8x and x^2.
The answer is
4x^2  (x^3)/3
To verify, differentiate it and see if you get 8xx^2 back again. 
Sorry, it is evaluate the indefinite integral: sqrt(8xx^2)

2y*y'=x/sqrt(x^216)