Algebra (math)

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At 7:00 am , Joe starts jogging at 6 mi/h. At 7:10 am. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 am?

  • Algebra (math) -

    joe would run for 30 minutes or 1/2 hour
    Ken would run for 20 minutes or 1/3 hour.

    JOe ran (1/2)(6) miles = 3 miles
    to run 3 miles in 1/3 hour, ken must have a speed of 3/(1/3) mph = ....

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