algebra
posted by Katherine .
So here's the problem:
6a^2 + 9a^2 all over 3a^2
The answer is suppose to be 2 + 3a^4
I keep getting the answer as 5.
Can you show me how to solve this problem correctly?

how about multiplying top and bottom of your fraction by a^2 to get
(6 + 9a^4)/3
= 2 + 3a^4
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