posted by AMY .
Considering the tube wherein NaOH (1 M) was added to benzoic acid.
a) what reaction would occur in the tube?
b) write a balance equation that supports your explanation above?
c) describe what would happen if u added HCL (6 M) to the same tube?
Have you changed compounds. Your earlier question concerned 4-aminoethyl benzoate. Straight benzoic acid would form a salt since it is an acid reacting with a base, NaOH.
ArCOOH + NaOH ==> H2O + ArCOONa where Ar is the benzene ring.
c). If HCl is added to the tube, HCl neutralizes the NaOH and reprecipirates the benzoic acid.