posted by Nina .
Formic acid is only readily soluble in water and in both 0.6 M NaHCO3 and 2.5 M NaOH.
give a brief explanation of the reaction for each
Same answer as above for hexanoic acid.
These are typical reactions between and acid and a bicarbonate, and an acid and a base. Sodium formate (a salt) and H2O are forming in both cases. CO2 is forming typically when a base reacts with a bicarbonate or a carbonate.
HCOOH + NaHCO3 ---> HCOONa + H2O + CO2
HCOOH + NaOH ---> HCOONa + H2O