math
posted by yugio .
how do we find the least residue of
1789 (mod 4), (mod 10), (mod 101)

If I remember modular arithmetic
1789(mod4) = 1
1789(mod10) = 9
1789(mod101) = 72
I don't know what you mean by "least residue"
Respond to this Question
Similar Questions

another college math question
Please teach me. I am completely blank with it. :( Let alpha = (3+sqrt(3))/2 belongs to Q[sqrt(3)]. Show that if x is congruent to 1 mod alpha, then x^3 is congruent to 1 (mod alpha)^3. Similarly, show that if x is congruent to 1 … 
math
how do we find the least residue of 1789 (mod 4), (mod 10), (mod 101) 
probability
how do we find the least residue of 1789 (mod 4), (mod 10), (mod 101) 
math
Which two is true as i'm confused A) 3+7 ß 10 mod 15 17 + 9 ß 4 mod 21 12 + 14 ß 0 mod 26 B) 4+11 ß 2 mod 13 9+7 ß 4 mod 12 13 + 13 ß 1 mod 25 C) 5+9 ß 4 mod 10 16 + 13 ß 3 mod 26 12 + 7 ß 6 mod 14 d)2+7 … 
Math
What are the 3 solutions? I'm stuck! 6x=15(mod 21) a=6,m=21,b=15 d=gcd(6,21)=3 solns. 6x=15(mod 21) 2x=5(mod 7) 21=6(3)+3 6+3(2)+0 0=66 6(216(3))=3 621+18=3 6( )21()=3 (216(3))(15)6=3 ? 
Math
Which Statements of congruence are true and which are false and why? 
math
Which Statements of congruence are true and which are false and why? 
Math
Which Statements of congruence are true and which are false and why? 
Math
Find all numbers $r$ for which the system of congruences: x == r mod 6 x == 9 mod 20 x == 4 mod 45 has a solution. 
math
Find the least residue of 7^5 mod 50 without using a calculator. so far I have 7=7 mod 50 7^5 = 7^5 mod 50 7^2 = 49 7^3=343 since 7^2=(1)mod50 and 7^3=(43)mod50 it follows that 7^6=7^2 * 7^3 = (1)(43) = 43 feel like this is wrong …