Hi i need to find x in 9^(2x-6)=6^(8x-5) So what i did was: 3^(4x-12)=6^(8x-5) log3(3)^(4x-12)=log3(6)^(8x-5) 4x-12=(8x-5)log3(6) now i'm stuck. and i actually feel that the whole thing is wrong. help, pls
Given log2=0.3010, log3=0.4771, log5=0.6690, and log7=0.8451... Find a.) log8 b) log5/7 c.) log1.5 d.) log3/14 e) log12 I didn't know how to do b, c, and d. I also don't know if log 12 is right. Answer: a.) 0.903 b.)?